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M F I »130 095 350 070 Determine Cc, and void ratio corresponding to a stress of tsf Solution 2 1 1 2 c log p log p e e C − − = 0581 log350 log130 095 070 Cc = − − = log log 13 095 e 0581 2 − = Therefore, e2 = 0841P ol i c y U W S c hool of O c e a nogr a phy i s c om m i t t e d t o m a i nt a i ni ng a pos i t i ve w or ki ng, r e s e a r c h a nd l e a r ni ng e nvi r onm e nt f r e e of i l l e ga l di s c r i m i na t i on, ha r a s s m e nt , i nt i m i da t i on a nd t he pe r c e pt i on t he r e of

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L I F HC B / S E w b ¹M F I W '0 / * m B &Description h,w = freqz (b,a,n) returns the n point frequency response vector h and the corresponding angular frequency vector w for the digital filter with transfer function coefficients stored in b and a h,w = freqz (sos,n) returns the n point complex frequency response corresponding to the secondorder sections matrix sos

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This list of all twoletter combinations includes 1352 (2 ×PART 1 MODULE 2 Now suppose we merge all of the elements of A with all of the elements of B to form a single, larger set {Citizen Kane, Casablanca, The Godfather, Gone With the Wind, Lawrence of Arabia, The Godfather Part 2, The Wizard of Oz, To Kill A Mockingbird}B F(A,B,C,D) = D (A' C') 6 a Since the universal gates {AND, OR, NOT can be constructed from the NAND gate, it is universal

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F(x)e sxdx Thus if Xis a continuous random ariablve with the PDF such that f X(x) = 0 for x<0, then 1 0 etxf X(x)dx= Lf X( t) Proposition 131 allows to show some of the properties of sums of independent random ariablesv we proved or stated before Example 137 (Sums of independent normal random ariables)vV f % ¸Question Abc=30 Ab= 24

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B 1 c >3 (MK 223) Simplify the follwoing functions into (1) sumofproducts and (2) product (a) F(A,B,C,D) = m (2,3,5,7,8,10,12,13) (b) F(W,X,Y,Z) = M (2,10,13) (a) F(A,B0, if x ≥ b;

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Page 1 ECE223, Solutions for Assignment #2 Chapter 2, Digital Design, M Mano, 3rd Edition 22) Simplify the following Boolean expression to a minimum number literalsSix radial lines applied to head 30 degrees apart ASTM A 490 Type 3 Heavy Series 90 X Symbol for identification of grade, ie, "490", applied to head C F S A 325 C F S A 3 2 5 M/C APPR Cardinal Fastener &Title show_temppl Author connorja Created Date AM

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Problem Ten (1738) Let Aj = { 2, 1, 0, 1, , j} Find n a) ∪ Aj j=1 Each Aj is the set { j}, so every Aj fully contains the sets Aj1 Aj2 etc as subsets Therefore, the union of the sets A1 through An is exactly AnWe can take this one step further and say that, since nAAlpha BBravo CCharlie DDelta EEcho FFoxtrot GGolf HHotel IIndia JJuliett KKilo LLima MMike NNovember OOscar26 2) of the possible 2704 (52 2) combinations of upper and lower case from the modern core Latin alphabetA twoletter combination in bold means that the link links straight to a Wikipedia article (not a disambiguation page) As specified at WikipediaDisambiguation#Combining_terms_on_disambiguation_pages,

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In December of 16, Winchester began offering special 30 WCF "Short Range" ammunition to be used for "small game where the more powerful cartridge is not necessary" as it was described in that catalogThe cartridge illustration was shown as the since cartridges contained a 100 gr lead bullet and 6 grains of powderB C 1 g V F;Step by step solution of a set of 2, 3 or 4 Linear Equations using the Substitution Method ab=30;ab=30 Tiger Algebra Solver

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dr, where F= x2yi− xy2jz3k, and C is the curve of intersection of the plane 3x 2y z = 6 and the cylinder x2 y2 = 4, oriented clockwise when viewed from above Solution Let S be the part of the plane 3x 2y z = 6 that lies inside the cylinder x2 y2 = 1, oriented downward Then C = ∂SAfter switching the 1's and 0's in the Kmap f = AC A'BC' B'C g Problem 2 0 points Katz 219a f (w,x,y,z) = w'x' x'y' Problem 3 4 points Katz 2c,d It's important to notice here that the question ask for the ProductofSums expression Many of you didn't do this To get obtain the product of sums expression from a kmap1, if x ≤ a A simple computation yields E(X) = ab 2 Var(X) = (b−a)2 12 M(s) = esb −esa s(b−a) When a = 0 and b = 1, this is known as the uniform distribution over the unit interval, f(x) = 1 1

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1 d I Q;You can calculate λc for the column, the read the value of φcFcr/Fy The column strength will be equal to φ c F cr /F y x (A g x F y ) EXAMPLE 32 Calculate the design strength of W14 x 74 with length of ft and pinned ends

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Example 5 X and Y are jointly continuous with joint pdf f(x,y) = (e−(xy) if 0 ≤ x, 0 ≤ y 0, otherwise Let Z = X/Y Find the pdf of Z The first thing we do is draw a picture of the support set (which in this case is the firstA n n u a l C h e c k l i s t o f Va s c u l a r P l a n t 8 9P o l i c y a n d d o c t r i n e i n C h a i r m a n , J o i n t Chiefs of Staff Instruction D and J o i n t P u b l i c a t i o n 3 – 1 3 3 I n J o i n t a n d Army operations, operations security is an i n f o r m a t i o n r e l a t e d c a p a b i l i t y i n t e g r a t e d by Information Operations as prescribed

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A ugust 11 (Wed) AT S C Team B ui l di ng E vent (4 009 30 P M) AT S C A ugust 12 (T hurs) AT S C Vocal Rehearsal (7 t o 9 30 P M) AT S C A ugust 13 (F ri ) AT S C Vocal Rehearsal (1 t o 3 P M) AT S C A ugust 15 (S un) AT S C Vocal Rehearsal (2 t o 4 P M) AT S CB • Courseware • Physics Discussion • Whiteboard • Shop • learn HTML • Graphic Calculator • Basic Calculator • Unit Converter • SI Prefixes • Equations • PhysicalO c n t D,ent˜aof l a e v ´

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1 Provase que se f n u a ı m´e e ´Or the rare dieresis, üThese are not considered separate letters Alphabet is el alfabeto in Spanish, but you can also say el abecedario which is a word made up of the first three letters of the alphabet (like saying ABCs)The Hungarian alphabet (Hungarian magyar ábécé) is an extension of the Latin alphabet used for writing the Hungarian language The alphabet is based on the Latin alphabet, with several added variations of lettersThe alphabet consists of the 26 letters of the ISO basic Latin alphabet, as well as 5 letters with an acute accent, 2 letters with an umlaut, 2 letters with a double acute accent

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´e g e r n t i 2 Se f(x,y) ≥ 0 n u a ı me ´e ´In the case of a single discrete RV, the pmf has a very concrete meaning f(x) is the probability that X = x If X is a single continuous random variable, thenW Nuclear Energy E = mc 2 J Quantum Energy DE = hf J NEWS • Demos • Physics Mail • Physics Forums • Search • iPhysics • MicroLabs a, &

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B T ' &M c a M X B c , Na a Sa C c Ja B , M Sa A a c L Ca , Na a Sa C cE x Acos 2x Bsin 2x To solve for A and B using the initial values we must first differentiate y (1227) y e x Acos 2x Bsin 2x e x 2Asin 2x 2os 2x Substituting the initial values gives the equations A 2 A 2B 1, which has the solutions A 2 B 1 2 The answer thus is (1228) y e x 2cos 2x 1 2 sin 2x Case of a double root If the discriminant a2

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Example Now suppose X,Y have density f(x,y) = ˆ e−x−y if x,y ≥ 0 0, otherwise Compute P(X Y ≤ t) 2 What does the pdf mean?O c n t D,ent˜aoogr´aficodef (G f) est´a acima do planoxyEnt˜aoovolumedos´olidoW que est´a abaixo de G f eacimadeD ´e d a d o p o r V(W)= $$ D f(x,y)dxdy Logo, para encontrar o volume do s´olidoW,integramosf(x,y)Spanish letters are all feminine la a, la be, la ce, etc You may be wondering about letters with accents like á, é, í, ó, and ú

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F(x) = b−x b−a, if x ∈ (a,b);Page 1 ECE223, Solutions for Assignment #3 Chapter 3, Digital Design, M Mano, 3rd Edition 33) Simplify the following Boolean functions, using threevariable mapsThe cross product (or vector product) between two vectors A and B is written as AxB The result of a crossproduct is a new vector We need to find its magnitude and direction (See section 37 in the text for more review) Magnitude AxB = A B sinθ Just like the dot product, θ is the angle between the vectors A and B when they are drawn

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